Consider a transformer that has 1,000 times more turns on the secondary side than on the primary side. How will this transformer change the voltage?

The transformer in question operates based on the principle of electromagnetic induction and the relationship between the number of turns in the primary and secondary coils. When a transformer has a secondary coil with 1,000 times more turns than the primary coil, it is configured as a step-up transformer.

In such transformers, the voltage in the secondary coil is directly proportional to the number of turns in that coil compared to the primary coil. The formula representing this relationship is:

[ \frac{V_s}{V_p} = \frac{N_s}{N_p} ]

Where ( V_s ) is the secondary voltage, ( V_p ) is the primary voltage, ( N_s ) is the number of turns in the secondary coil, and ( N_p ) is the number of turns in the primary coil. Given that ( N_s ) is 1,000 times ( N_p ), the equation shows that the secondary voltage will be 1,000 times greater than the primary voltage.

Therefore, this transformer will increase the voltage by a factor of 1,000. This means that if the primary voltage is, for example, 10 volts, the secondary voltage will be 10,000 volts as a result of this